How do you solve for y in #1+7y=5x-2#?
1 Answer
Mar 22, 2017
Explanation:
Isolate 7y on the left side of the equation by subtracting 1 from both sides.
#cancel(1)cancel(-1)+7y=5x-2-1#
#rArr7y=5x-3# divide both sides by 7
#(cancel(7) y)/cancel(7)=1/7(5x-3)#
#rArry=1/7(5x-3)" or "#
#y=5/7x-3/7#
