How do you solve for y : #4x- 3y = 12#?

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Answer 1 · 2015-04-10T11:14:34

#4x-3y=12#

Rearrange the equation so that #3y# is isolated from other values:

#4x-12=3y#

Now, we can find #y# by dividing the all values in the equation by 3.

#(4x-12)/3=(3y)/3#

#4/3x-4 = y#

#y=4/3x-4#