How do you solve for x in #ax+b=cx+d #? Algebra Linear Equations Multi-Step Equations with Like Terms 1 Answer Bill Jorgensen Jun 5, 2018 #x=(d-b)/(a-c), a-c!=0# Explanation: Isolate the terms with x: #ax+b=cx+d# #ax-cx=d-b# factor out x: #x(a-c)=d-b# divide: #x=(d-b)/(a-c), a-c!=0# Answer link Related questions How do you solve multi step equations by combining like terms? How do you solve multi step equation #w + w + 12 = 40#? How do you solve #3p + 4p + 37 = 79#? How do you solve for f: #f-1+2f+f-3=-4#? How do you combine like terms? How do you combine like terms for #-7mn-2mn^2-2mn + 8#? How do you combine like terms for #3x^2 + 21x + 5x + 10x^2#? What is a term? How do you solve #3v+5-7v+18=17#? How do you solve for x in #5x + 7x = 72#? See all questions in Multi-Step Equations with Like Terms Impact of this question 10052 views around the world You can reuse this answer Creative Commons License