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How do you solve for x in # 2^ logx = 1/4#?

1 Answer

Dec 22, 2015

#x=0.01#

Explanation:

Note that
#color(white)("XXX")1/4=1/(2^2)=2^(-2)#

So if #2^(log(x)) = 1/4#
then
#color(white)("XXX")log(x)=-2#

#color(white)("XXX")10^(-2) = x# (based on definition of log)

#color(white)("XXX")x=1/100 = 0.01#

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