How do you solve for u in #8u=3u+35#?

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Answer 1 · 2018-04-23T08:56:03

#u=7#

#8u= 3u + 35#

Subtract #3u# from both sides

#8u-3u=5u and 3u-3u= 0 (0u)#

So

#5u= 35#

Divide both sides by #5#

#(5u)/5 = u \ "as" \ 5/5=1 and 35/5=7#

So

#u= 7 #