How do you solve for the exact solutions in the interval [0,2pi] of #4 sin x cos x= 1#?

Question

How do you solve for the exact solutions in the interval [0,2pi] of #4 sin x cos x= 1#?

1 Answer

Impact of this question

2379 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-15T05:46:34

#pi/6 and (5pi)/12#

Explanation:

Use the trig identity: sin 2a = 2sin a.cos a
4sin x.cos x = 2sin 2x = 1
#sin 2x = 1/2#
Trig table and unit circle -->
#sin 2x = 1/2# --> #2x = pi/6# and # 2x = (5pi)/6#
a. 2x = pi/6 --> #x = pi/12#
b. x = (5pi)/6 --> #x = (5pi)/12#

Science

Math

Humanities

... and beyond

How do you solve for the exact solutions in the interval [0,2pi] of #4 sin x cos x= 1#?

1 Answer

Explanation:

Related questions

Impact of this question