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How do you solve for r in #S=2πrh#?

1 Answer

Jul 12, 2016

#S/(2pih) = r#

Explanation:

Divide both sides by #2pih# to get #r# by itself on the right side:

#S/(2pih) = (cancel"2"cancel"pi"rcancel"h")/(cancel"2"cancel"pi"cancel"h")#

#S/(2pih) = r#

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