How do you solve for r in #S=2πrh#? Algebra Linear Equations Multi-Step Equations with Like Terms 1 Answer Kayla Jul 12, 2016 #S/(2pih) = r# Explanation: Divide both sides by #2pih# to get #r# by itself on the right side: #S/(2pih) = (cancel"2"cancel"pi"rcancel"h")/(cancel"2"cancel"pi"cancel"h")# #S/(2pih) = r# Answer link Related questions How do you solve multi step equations by combining like terms? How do you solve multi step equation #w + w + 12 = 40#? How do you solve #3p + 4p + 37 = 79#? How do you solve for f: #f-1+2f+f-3=-4#? How do you combine like terms? How do you combine like terms for #-7mn-2mn^2-2mn + 8#? How do you combine like terms for #3x^2 + 21x + 5x + 10x^2#? What is a term? How do you solve #3v+5-7v+18=17#? How do you solve for x in #5x + 7x = 72#? See all questions in Multi-Step Equations with Like Terms Impact of this question 28378 views around the world You can reuse this answer Creative Commons License