How do you solve for n in (9n+4)+(3n20.75)=180?

1 Answer
Jul 7, 2018

n1=2202696 or n2=9622026

Explanation:

Simplifying your equation

3n2+9n+434180=0

we have

434180=1633604=7074

so we have to solve

3n2+9n7074=0
dividing by 3 we get

n2+3n70712=0

by the quadratic formula we get

n1,2=32±3676

this is

n1,2=32±22026

so we get

n1=220296

n2=16(9+2202)