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How do you solve for #log_x 125 = 3#?

1 Answer

Jan 7, 2016

I found #x=5#

Explanation:

I would use the definition of log and write:
#125=x^3#
Change #125# into #5^3#:
#5^3=x^3#
So that to be equal we need #x=5#.

Spero sia utile!

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