How do you solve for $log_7 ( 1/49) = x$ ?

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Answer 1 · 2015-12-30T14:52:48

$x=-2$

By the definition of the log function, we may rewrite this equation in exponential form as follows :

$log_7(1/49)=x iff 7^x=1/49$

$iffx=-2$

How do you solve for log_7 ( 1/49) = xlog_7 ( 1/49) = x?