How do you solve for #log_4 x = 3#?

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How do you solve for #log_4 x = 3#?

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Answer 1 · 2015-12-09T14:53:16

I found #x=64#

Explanation:

You can find #x# by changing the log into an exponential taking the base, #4#, from the left and "pushing up" #3# on the right:
#log_4x=3#
so:
#x=4^3=64#

hope it helps!

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How do you solve for #log_4 x = 3#?

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