How do you solve for $log_4 x = -2$ ?

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Answer 1 · 2018-07-21T06:35:51

$x=1/16$

From the definition of logarithm, if $log_ab=c$ then $b=a^c$

Hence as $log_4x=-2$ ,

we have $4^(-2)=x$

i.e $x=4^(-2)=1/4^2=1/16$

How do you solve for log_4 x = -2log_4 x = -2?