How do you solve for K in #F= 9/5(K-273)+32#?

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Answer 1 · 2016-05-17T20:28:27

#K=5/9(F-32)+273#

Subtract 32 from both sides

#F-32=9/5(K-273)#

Multiply both sides by #5/9#

#5/9(F-32)=(9/5xx5/9)(K-273)#

#5/9(F-32)=1xx(K-273)#

Add 273 to both sides

#K=5/9(F-32)+273#