How do you solve for K in $F= 9/5(K-273)+32$ ?

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Answer 1 · 2016-05-17T20:28:27

$K=5/9(F-32)+273$

Subtract 32 from both sides

$F-32=9/5(K-273)$

Multiply both sides by $5/9$

$5/9(F-32)=(9/5xx5/9)(K-273)$

$5/9(F-32)=1xx(K-273)$

Add 273 to both sides

$K=5/9(F-32)+273$

How do you solve for K in F= 9/5(K-273)+32F= 9/5(K-273)+32?