How do you solve for d in #cy-d=4d#?

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Answer 1 · 2016-03-06T05:26:30

#d=(cy)/5#

#cy-d=4d#

What we do on one side must be done on thee other side also
(Golden rule of algebra)

Add #d# both sides

#rarrcy-d+d=4d+d#

#rarrcy=5d#

Divide both sides by #5#

#rarr(cy)/5=(cancel5d)/cancel5#

#rArrd=(cy)/5#