How do you solve for b in #A = 1/2h(B + b)#?

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Answer 1 · 2015-07-23T15:12:32

You isolate it on one side of the equation.

To solve your expression for #b#, you need to isolate it on one side of the equation.

One way in which you can do that is by multiplying boths sides of the equation by 2 to get rid of the fraction.

#2 * A = cancel(2) * 1/cancel(2) * h(B + b)#

#2A = h(B + b)#

Now divide both sides of the equation by #h# to get

#(2A)/h = cancel(h)/cancel(h) * (B + b)#

#(2A)/h = B + b#

Finally, move #B# on the other side of the equation by subtracting it from both sides of the equation

#(2A)/h - B = cancel(B) - cancel(B) + b#

And there you have it, #b# is equal to

#b = color(green)((2A)/h - B)#