How do you solve for a in $\frac{\sqrt{a - 3 b}}{2} = c$ $sqrt(a-3b)/2 = c$ ?

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Answer 1 · 2017-10-28T16:05:35

Given: $\frac{\sqrt{a - 3 b}}{2} = c$ $sqrt(a-3b)/2 = c$

Multiply both sides by 2:

$\sqrt{a - 3 b} = 2 c$ $sqrt(a-3b) = 2c$

Square both sides:

$a - 3 b = 4 c^{2}$ $a-3b = 4c^2$

Add 3b to both sides:

$a = 4 c^{2} + 3 b$ $a = 4c^2+3b$

How do you solve for a in √a−3b2=csqrt(a-3b)/2 = c?