How do you solve $f(x)=x^2-x+3$ using the quadratic formula?

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Answer 1 · 2017-07-19T11:25:19

See a solution process below:

For $f(x) = ax^2 + bx + c$ , the values of $x$ which are the solutions to the equation for $0$ are given by:

$x = (-b +- sqrt(b^2 - 4ac))/(2a)$

Substituting $1$ for $a$ ; $-1$ for $b$ and $3$ for $c$ gives:

$x = (-(-1) +- sqrt((-1)^2 - (4 * 1 * 3)))/(2 * 1)$

$x = (1 +- sqrt(1 - 12))/2$

$x = (1 +- sqrt(-11))/2$

How do you solve f(x)=x^2-x+3 f(x)=x^2-x+3 using the quadratic formula?