How do you solve #f-(-7/10)=-4/5#?

1 Answer
Shantelle
May 5, 2018

#f = -3/2#

Explanation:

#f-(-7/10) = -4/5#

First, we know that two negative signs cancel each other and become a positive, so it becomes:
#f + 7/10 = -4/5#

Since we need to find the variable #f#, we need to make it alone.

Subtract #color(blue)(7/10)# from both sides of the equation:
#f + 7/10 quadcolor(blue)(-quad7/10) = -4/5 quadcolor(blue)(-quad7/10)#

#f = -4/5 - 7/10#

To simplify the right side, we need to make both fractions have the same denominator. To do so, let's multiply #-4/5# by #color(blue)(2/2)#:
#f = (-4/5 quadcolor(blue)(*quad2/2)) - 7/10#

#f = -8/10 - 7/10#

Combine denominators:
#f = (-8-7)/10#

#f = -15/10#

Divide numerator and denominator by #color(blue)5#:
#f = -15/10 quadcolor(blue)(-:quad5/5)#

#f = -3/2#

Hope this helps!

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