How do you solve $e^-x = 9$ ?

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How do you solve $e^-x = 9$ ?

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Answer 1 · 2016-11-29T14:30:47

I got: $x=-ln(9)=-2.19722$

Explanation:

We can take the natural log of both sides:
$ln(e^-x)=ln(9)$
where the $ln$ and $e$ cancel and you are left with:
$-x=ln(9)$
and so:
$x=-ln(9)=-2.19722$

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How do you solve $e^-x = 9$ ?

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How do you solve e^-x = 9e^-x = 9?

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How do you solve $e^-x = 9$ ?