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How do you solve #(e^4)^x * e^(x^2) = e^12#?

1 Answer

Jul 8, 2016

#e^(4x) xx e^(x^2) = e^12#

By the rule #a^n xx a^m = a^(n + m)#

#x^2 + 4x - 12 = 0#

#(x + 6)(x - 2) = 0#

#x = -6 and 2#

Hopefully this helps!

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