How do you solve #e^(3x)=4#?

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Answer 1 · 2018-03-27T13:10:52

#x=ln4/3~~0.46#

Given: #e^(3x)=4#

Take natural logarithm of both sides.

#ln(e^(3x))=ln4#

#3x=ln4#

Divide by #3#.

#(color(red)cancelcolor(black)3x)/(color(red)cancelcolor(black)3)=ln4/3#

#x=ln4/3#