How do I find the inverse of #e^x#?

1 Answer
Amory W.
Sep 5, 2014

The answer is #y=ln x#.

We find the answer the same way we find any inverse; we swap #x# and #y# then solve.

#y=e^x#
#x=e^y# swap
#ln x=ln (e^y)# take logarithm of both sides
#ln x=y#

#ln# and #e# functions cancel each other because they are inverses.

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