How do you solve $- d = 3 sqrt (d - 2)$ ?

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Answer 1 · 2016-03-07T04:06:22

You must first isolate the square root.

$-d = 3sqrt(d - 2)$

$-d/3 = sqrt(d - 2)$

You must square both sides of the equation to get rid of the equation.

$(-d/3)^2 = (sqrt(d - 2))^2$

$d^2/9 = d - 2$

$d^2 = 9(d - 2)$

$d^2 = 9d - 18$

$d^2 - 9d + 18 = 0$

$(d - 6)(d - 3) = 0$

$d = 6 and d= 3$

Check your solutions back in the equation. Neither work, so there is no solution. Therefore, the solution is ${O/}$ .

Practice exercises:

Solve for x:

a) $sqrt(2x + 1) = sqrt(4x) - 1$

b). $sqrt(2x + 2) + sqrt(9x - 2) = 12$

Challenge problem

Solve the following system.

$sqrt(8x + 1) + sqrt(y + 4) = 3x - 1$
$sqrt(11x + 3) - sqrt(y - 1) = x + 1$

Good luck!

How do you solve - d = 3 sqrt (d - 2)- d = 3 sqrt (d - 2)?