How do you solve #d^2+5d+6=0# using the quadratic formula?

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Answer 1 · 2015-08-10T07:43:01

The solutions for the equation are:
#color(blue)(x=-2#

#color(blue)(x=-3#

#d^2+5d+6=0 #

The equation is of the form #color(blue)(ad^2+bd+c=0# where:

#a=1, b=5, c=6#

The Discriminant is given by:
#Delta=b^2-4*a*c#

# = (5)^2-(4*1*6)#

# = 25 - 24 = 1#

As #Delta=0# there is only one solution.

The solutions are found using the formula:

#x=(-b+-sqrtDelta)/(2*a)#

#x = ((-5)+-sqrt(1))/(2*1) = (-5+-1)/2#

The solutions for the equation are:
#x =(-5+1)/2 , x=-4/2,color(blue)(x=-2#

#x =(-5-1)/2 , x=-6/2,color(blue)(x=-3#