How do you solve #cscx-2=0#?

1 Answer

Aug 17, 2016

#pi/6 + 2kpi#
#(5pi)/6 + 2kpi#

Explanation:

#csc x - 2 = 0#
#1/(sin x) - 2 = 0#
#(1 - 2sin x)/sin x = 0#
1 - 2sin x = 0 --> (condition sin x different to zero)
#sin x = 1/2#
Trig table and unit circle give 2 solution arcs:
a. #x = pi/6 + 2kpi#
b. #x = (5pi)/6 + 2kpi#

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How do you solve #cscx-2=0#?

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