How do you solve ${csc}^{2} x - 2 = 0$ $csc^2x-2=0$ ?

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Answer 1 · 2016-04-19T18:25:20

$S = {\pm \frac{π}{4} + 2 π n, \pm \frac{3 π}{4} + 2 π n}$ $S={+-pi/4+2pin,+-(3pi)/4+2pin}$

${csc}^{2} x = 2$ $csc^2x=2$

$csc x = \pm \sqrt{2}$ $cscx=+-sqrt2$

$x = {csc}^{- 1} (\pm \sqrt{2})$ $x=csc^-1 (+-sqrt2)$

$x = {sin}^{- 1} (\pm \frac{1}{\sqrt{2}})$ $x=sin^-1 (+- 1/sqrt2)$

$x = \pm \frac{π}{4} + 2 π n, \pm \frac{3 π}{4} + 2 π n$ $x= +-pi/4+2pin,+-(3pi)/4+2pin$

$S = {\pm \frac{π}{4} + 2 π n, \pm \frac{3 π}{4} + 2 π n}$ $S={+-pi/4+2pin,+-(3pi)/4+2pin}$

How do you solve csc^2x-2=0csc2x−2=0csc^2x-2=0?