How do you solve ${csc}^{2} θ - csc θ = 0$ $csc^2 theta - csc theta = 0$ ?

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Answer 1 · 2016-04-18T16:52:50

$S = {\frac{π}{2} + 2 π n}$ $S={pi/2 +2pin}$

$csc θ (csc θ - 1) = 0$ $csc theta(csc theta-1)=0$

$csc θ = 0 or csc θ - 1 = 0$ $csc theta=0 or csc theta -1 =0$

$θ = {csc}^{- 1} 0 or csc θ = 1 \to θ = {csc}^{- 1} (1)$ $theta=csc^-1 0 or csc theta =1 ->theta=csc^-1(1)$

$θ = {sin}^{- 1} (\frac{1}{0}) or θ = {sin}^{- 1} (\frac{1}{1})$ $theta=sin^-1(1/0) or theta=sin^-1(1/1)$

$θ = n o s o l u t i o n, θ = \frac{π}{2} + 2 π n$ $theta=no solution, theta=pi/2 +2pin$

$S = {\frac{π}{2} + 2 π n}$ $S={pi/2 +2pin}$

How do you solve csc^2 theta - csc theta = 0csc2θ−cscθ=0csc^2 theta - csc theta = 0?