How do you solve $cosx(tanx-sqrt3)=0$ and find all solutions in the interval $0<=x<360$ ?

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How do you solve $cosx(tanx-sqrt3)=0$ and find all solutions in the interval $0<=x<360$ ?

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Answer 1 · 2017-07-04T21:47:47

$pi/3; pi/2; (4pi)/3, (3pi)/2$

Explanation:

$f(x) = cos x(tan x - sqrt3) = 0$
Either factor should be zero.
a. $cos x = 0$ --> Unit circle gives -->
$x = pi/2$ and $x = (3pi)/2$
b. $tan x = sqrt3$ --> trig table and unit circle give -->
$x = pi/3$ and $x = pi/3 + pi = (4pi)/3$

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How do you solve $cosx(tanx-sqrt3)=0$ and find all solutions in the interval $0<=x<360$ ?

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How do you solve $cosx(tanx-sqrt3)=0$ and find all solutions in the interval $0<=x<360$ ?