How do you solve $cosx=sqrt3/2$ ?

Question

24540 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-22T14:02:56

$x=2npi+-pi/6$ , where $n$ is an integer.

As $cosx=sqrt3/2$ , $x$ is positive and hence can be in

either first quadrant i.e. $x=pi/6$ or in fourth quadrant i.e. $x=-pi/6$

Further adding $+-2pi$ to $x$ too does not change value of $cosx$

Hence $x=2npi+-pi/6$ , where $n$ is an integer.

How do you solve cosx=sqrt3/2 cosx=sqrt3/2?