How do you solve #cosx(6sinx - 5) = 0#?
1 Answer
Feb 5, 2016
# x = 0.99 , pi/2 , 2.15 , (3pi)/2 #
Explanation:
cosx ( 6sinx - 5 ) = 0
hence cosx = 0 or 6sinx - 5 = 0 →
# sinx = 5/6 # solve cosx = 0
# rArr x = pi/2 , (3pi)/2 # solve
# sinx = 5/6 rArr x = 0.99 , x = (pi - 0.99) = 2.15 #
