How do you solve $cos 3 x = \frac{1}{\sqrt{2}}$ $cos3x=1/sqrt2$ ?

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How do you solve $cos 3 x = \frac{1}{\sqrt{2}}$ $cos3x=1/sqrt2$ ?

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Answer 1 · 2017-05-09T18:44:57

So as our $3$ $3$ is next to the $x$ $x$ and not the $cos$ $cos$ , we need to divide by $3$ $3$ right at the end. First step is ${cos}^{- 1}$ $cos^(-1)$ .
${cos}^{- 1} (\frac{1}{\sqrt{2}}) = 45$ $cos^(-1)( 1/sqrt2) = 45$
$\frac{45}{3} = 15$ $45/3 = 15$ .
If the questions asks about limits and says something along the lines of 'between $0$ $0$ and $360$ $360$ ', you'll need to find several others answers along with the $45$ $45$ before you divide by $3$ $3$ .

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How do you solve $cos 3 x = \frac{1}{\sqrt{2}}$ $cos3x=1/sqrt2$ ?

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How do you solve $cos 3 x = \frac{1}{\sqrt{2}}$ $cos3x=1/sqrt2$ ?