How do you solve $cos2xsinx+sinx=0$ in the interval [0,360]?

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How do you solve $cos2xsinx+sinx=0$ in the interval [0,360]?

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Answer 1 · 2016-10-25T13:43:46

$0, pi/2, pi, 2pi$

Explanation:

cos 2x.sin x + sin x = 0
sin x(cos 2x + 1) = 0
Solve this equation for x.
a. sin x = 0 --> $x = 0, x = pi, and x = 2pi$
b. cos 2x = 1 = 0
cos 2x = -1
$cos 2x = cos pi$
$2x = pi$
$x = pi/2$
Answers for $(0, 2pi)$ :
$0, pi/2, pi, 2pi$

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How do you solve $cos2xsinx+sinx=0$ in the interval [0,360]?

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How do you solve $cos2xsinx+sinx=0$ in the interval [0,360]?