How do you solve #cos2x=sin^2x-2#?
1 Answer
Feb 26, 2017
Explanation:
Use identity:
cos 2x = 1 - 2sin^2 x
In this case:
1 - 2sin^2 x = sin^2 x - 2
Unit circle -->
sin x = 1 -->
sin x = -1 -->
