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How do you solve #Cos(x - pi/6) = -1/2#?

1 Answer

Apr 17, 2016

#S={(5pi)/6 +2pin, -pi/2 + 2pin}#

Explanation:

#x-pi/6 =cos^-1 (-1/2)#

#x-pi/6 = +- (2pi)/3 + 2pin#

#x= pi/6 +- (2pi)/3 +2pin#

#x=(5pi)/6 +2pin, -pi/2 + 2pin#

#S={(5pi)/6 +2pin, -pi/2 + 2pin}#

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