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How do you solve #cos(t+pi/6)=1/2#?

1 Answer

Harish Chandra Rajpoot

Jul 24, 2018

#t=2k\pi\pm\pi/3-\pi/6#
Where, #k# is any integer

Explanation:

#\cos(t+\pi/6)=1/2#

#\cos(t+\pi/6)=\cos(\pi/3)#

#t+\pi/6=2k\pi\pm\pi/3#

#t=2k\pi\pm\pi/3-\pi/6#

Where, #k# is any integer i.e. #k=0, \pm1, \pm2, \pm3, \ldots#

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