How do you solve Cos(pi/2 * x - 1) = 0?

1 Answer
Cesareo R.
May 13, 2016

x =(2 + (1 + 4 k) pi)/pi, k = {0,pm 1,pm 2,..}

Explanation:

The equation cos(theta)=0 verifies for all theta = pi/2+2k pi with k = {0,pm 1,pm 2,..}
Then pi/2x-1 must be of the form pi/2+2k pi. Equating
pi/2x-1=pi/2+2k pi Solving for x we get
x =(2 + (1 + 4 k) pi)/pi, k = {0,pm 1,pm 2,..}

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