Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve #cos^3/sinx=cotx#?

1 Answer

Jun 4, 2015

All the solutions are x=0,#pi/2, pi, (3pi)/2, 2pi#

Write #cos^3 x= sinx cotx = cos x#

#(cos^3x -cosx)=0#

#cosx(cos^2x-1)=0#

For cos x=0, x=#pi/2, (3pi)/2#,

For #cos^2x#-1=0, cos x= 1, -1

For cos x=1, x=0, #2pi#

For cos x= -1, x= #pi#

Related questions

See all questions in Solving Trigonometric Equations

Impact of this question

5655 views around the world

You can reuse this answer
Creative Commons License