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How do you solve $cos^3/sinx=cotx$ ?

1 Answer

Jun 4, 2015

All the solutions are x=0, $pi/2, pi, (3pi)/2, 2pi$

Write $cos^3 x= sinx cotx = cos x$

$(cos^3x -cosx)=0$

$cosx(cos^2x-1)=0$

For cos x=0, x= $pi/2, (3pi)/2$ ,

For $cos^2x$ -1=0, cos x= 1, -1

For cos x=1, x=0, $2pi$

For cos x= -1, x= $pi$

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