How do you solve #cos(2t)=1/2#?
1 Answer
Nov 26, 2015
Since
#x=pi/3 + 2k\pi# #x=5/3 pi + 2k\pi# ,
We simply need to substitute
#2t=pi/3 + 2k\pi# #2t=5/3 pi + 2k\pi#
From which we have
#t=pi/6 + k\pi# #t=5/6 pi + k\pi#
