How do you solve by factoring $6x^2 - x - 3= 0$ ?

Question

2000 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-30T14:47:06

To factor a trinomial of the form $y = ax^2 + bx + c, a != 1$ , you must find two numbers so that they multiply to $a xx c$ and they add to b.

Going through the factors of 18: $(-1, 18); (18, -1); (6,-3); (-3, 6); (-9,2); (-2, 9)$ , we see that none of those pairs add to -1.

Thus, we can say that this quadratic equation is non factorable; it can only be solved by the quadratic formula or completing the square.

Hopefully this helps.

How do you solve by factoring 6x^2 - x - 3= 06x^2 - x - 3= 0?