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How do you solve and write the following in interval notation: #6<7/2a+(-8)#?

1 Answer

Shwetank Mauria

Aug 15, 2016

#a>4# and in interval notation, this is written as #(4,oo)#.

Explanation:

As #6<7/2a+(-8)#, we have

#6+8<7/2a# or

#7/2a>14# or

#a>14×2/7# or

#a>4# and in interval notation, it can be written as #(4,oo)#.

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