How do you solve and write the following in interval notation: #|2x + 3| <9#?

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Answer 1 · 2017-02-11T06:38:04

#x in ]-6;3[#

The given inequality is equivalent to:

#-9<2x+3<9#

let's subtract 3 to all the terms and get:

#-12<2x<6#

then divide all terms by 2:

#-6 < x<3#

that is, in interval notation:

#x in ]-6;3[#