How do you solve and check your solutions to #48=8c#?

2 Answers
John D.
May 24, 2017

Divide both sides by 8 to get that #c=6#.
Then, plug in #6# for #c# and check to make sure the equation is true.

Explanation:

To solve the equation, you need to get #c# by itself.

How do we do that? Well, since both sides of the equation are equal, we can divide both sides of the equation by #8# and they will still be equal.

#color(white)"X...."48 = 8c#

#48 div 8 = 8c div 8#

#color(white)"X.-.-."6 = c#

This tells us that #c# is 6.
Now, we need to check our solution. We do this by "plugging in" 6 for #c# in the equation, and seeing if it makes it true.

#48 =^? 8c#

#48 =^? 8times6#

#48 =^color(limegreen)(sqrt()) 48#

So our solution is correct! #c=6#.

JS
May 24, 2017

#c=6#

Explanation:

The idea is to isolate c if you will. In order to do that, we need to dive both sides of the equation by 8.

#48/8=8c/8#

The 8 cancels out on the right side, leaving us with:

#6=c#

To check your answer, simply take the value of c that you found and plug it back into the original equation.

#48=8(6)#
#48=48#

Since the equation above is correct, our answer is correct.

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