How do you solve $abs(y - 8) +6 =15$ ?

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Answer 1 · 2015-04-29T11:52:08

$abs(y-8) + 6 = 15$
is equivalent to
$abs(y-8) = 9$

If $(y-8)$ is negative this is equivalent to
$8-y = 9$
$y=-1$

If $(y-8)>=0$ this is equivalent to
$y-8=9$
$y=17$

So $y epsilon {-1,17}$

How do you solve abs(y - 8) +6 =15 abs(y - 8) +6 =15?