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How do you solve # abs(y - 8) +6 =15#?

1 Answer

Apr 29, 2015

#abs(y-8) + 6 = 15#
is equivalent to
#abs(y-8) = 9#

If #(y-8)# is negative this is equivalent to
#8-y = 9#
#y=-1#

If #(y-8)>=0# this is equivalent to
#y-8=9#
#y=17#

So #y epsilon {-1,17}#

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