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How do you solve #a^3 = 4a #?

1 Answer

Shwetank Mauria

Sep 27, 2016

#a=0# or #a=-2# or #a=2#

Explanation:

#a^3=4a#

#hArra^3-4a=0# or

#a(a^2-4)=0# or

#a(a^2-2^2)=0# or

#a(a+2)(a-2)=0#

Hence either #a=0# or #a+2=0# or #a-2=0# i.e.

#a=0# or #a=-2# or #a=2#

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