How do you solve #a/2+a/3=5#?

Question

1258 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-30T17:30:39

#a =6#

#a/2 + a/3 = 5#

The L.C.M of #2# and #3# is #2xx3=6#

#(axx3)/(2xx3) + (axx2)/(3xx2) = 5#

#(3a)/(6) + (2a)/(6) = 5#

# (5a)/(6) = 5#

# 5a = 5 xx 6#

# 5a =30#

#a =30/5#

#a =6#