How do you solve $9y² = 16$ ?

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Answer 1 · 2016-03-28T14:05:16

$y=4/3$

$color(blue)(9y^2=16$

Divide both sides by $9$

$rarr(cancel9y^2)/cancel9=16/9$

$rarry^2=16/9$

Take the square root of both sides

$rarrsqrt(y^2)=sqrt(16/9)$

$rarry=sqrt(16/9)$

Remember that $color(brown)(sqrt(a/b)=sqrta/sqrtb$

$:.sqrt(16/9)=sqrt16/sqrt9$

$rarry=sqrt16/sqrt9$

$color(green)(rArry=4/3=1.bar9$

Remember that the $bar9$ means it is repeating...

Eg. $3.555555555..$ can be written as $3.bar5$

$:.4/3=1.999999999..$ is written as $1.bar9$

How do you solve 9y² = 169y² = 16?