How do you solve #9y² = 16#?

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Answer 1 · 2016-03-28T14:05:16

#y=4/3#

#color(blue)(9y^2=16#

Divide both sides by #9#

#rarr(cancel9y^2)/cancel9=16/9#

#rarry^2=16/9#

Take the square root of both sides

#rarrsqrt(y^2)=sqrt(16/9)#

#rarry=sqrt(16/9)#

Remember that #color(brown)(sqrt(a/b)=sqrta/sqrtb#

#:.sqrt(16/9)=sqrt16/sqrt9#

#rarry=sqrt16/sqrt9#

#color(green)(rArry=4/3=1.bar9#

Remember that the #bar9# means it is repeating...

Eg.#3.555555555..# can be written as #3.bar5#

#:.4/3=1.999999999..# is written as #1.bar9#