How do you solve $9v^2-8=0$ using the quadratic formula?

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Answer 1 · 2016-12-01T17:32:55

$(2sqrt2)/3$

considering quadratic formula having a=9, b=0 and c=-8
Therefore

$v=-b+-sqrt(b^2-4ac)/(2a) = 0+-sqrt(0-4*(9)*(-8))/(2*(9))=+-sqrt288/18 =+-sqrt(2*2*2*2*2*3*3)/18 = (12 sqrt2)/18 = (2sqrt2)/3$

How do you solve 9v^2-8=09v^2-8=0 using the quadratic formula?