How do you solve 9p^2-15p-6=0?
1 Answer
May 10, 2016
Explanation:
0 = 9p^2-15p-6
=3(3p^2-5p-2)
=3(3p^2-6p+p-2)
=3(3p(p-2)+1(p-2))
=3(2p+1)(p-2)
Hence:
p=-1/2 orp=2
0 = 9p^2-15p-6
=3(3p^2-5p-2)
=3(3p^2-6p+p-2)
=3(3p(p-2)+1(p-2))
=3(2p+1)(p-2)
Hence:
p=-1/2 orp=2