How do you solve $9(x+2)= 5[11-2(2-x)+3]$ ?

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Answer 1 · 2018-04-04T02:49:24

$color(maroon)(x = - 32$

$9(x+20 = 5 [11 - 2(2 -x) + 3]$

$9(x+2) = 5 * 11 - 5 * 2 * (2 - x) + 5 * 3, color(blue)(" removing [ ] bracket"$

$9x + 18 = 55 - 20 + 10x + 15, color(green)(" Removing () braces "$

$9x - 10x = 55 - 20 + 15 - 18. color(crimson)(" bringing like terms together"$

$-x = 70 - 38 = 32$

$color(maroon)(x = - 32$

Answer 2 · 2018-04-04T02:53:40

$x = -32$

$9(x+2) = 5[11-2(2-x)+3]$

Expand and Simplify Both Sides (Following Bedmas)

$9x+18 = 5[11-4+2x+3]$

$9x+18 = 5[10+2x]$

$9x+18 = 50+10x$

Isolate for $x$

$18 - 50 = 10x - 9x$

$-32 = x$

How do you solve 9(x+2)= 5[11-2(2-x)+3]9(x+2)= 5[11-2(2-x)+3]?