How do you solve $9 + \sqrt{6 - 11 x} = 45$ $9+sqrt(6-11x)=45$ ?

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How do you solve $9 + \sqrt{6 - 11 x} = 45$ $9+sqrt(6-11x)=45$ ?

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Answer 1 · 2017-01-19T22:34:23

I got: $x = - \frac{1290}{11}$ $x=-1290/11$

Explanation:

Let us first rearrange it:
$\sqrt{6 - 11 x} = 45 - 9$ $sqrt(6-11x)=45-9$
$\sqrt{6 - 11 x} = 36$ $sqrt(6-11x)=36$
square both sides:
${(\sqrt{6 - 11 x})}^{2} = 36^{2}$ $(sqrt(6-11x))^2=36^2$
$6 - 11 x = 1296$ $6-11x=1296$
$- 11 x = 1290$ $-11x=1290$
$x = - \frac{1290}{11}$ $x=-1290/11$

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How do you solve $9 + \sqrt{6 - 11 x} = 45$ $9+sqrt(6-11x)=45$ ?

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How do you solve 9+√6−11x=459+sqrt(6-11x)=45?

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How do you solve $9 + \sqrt{6 - 11 x} = 45$ $9+sqrt(6-11x)=45$ ?